Answer:
(6, 7) and (-2, -1)
Explanation:
if y=x+1 intersects with y=x^2-3x-11
then we need to find x and y such that both of those equations are true.
If y = x + 1 is true and y=x^2-3x-11, then
y - y = x^2-3x-11 - x - 1 is also true
0 = x^2 - 4x - 12
use your preferred method to solve the quadratic equation
0 = (x - 6)(x + 2)
x = 6 or x = -2
now for each x we take y from either equation, but y = x + 1 is simpler.
for x = 6 the coordinates are (6, 7) and for x = -2 the coordinates are (-2, -1)