Question

In a reaction where an OH group is substituted with a Cl, 15.02 g of 3-phenyl-2-butanol (MW=150.2 g/mol) is the starting material. What is the theoretical yield in grams of the product? (the product of the above reaction has a molecular weight of 168.1 g/mol)

Answer 1

16.81 g of C₁₀H₁₃Cl

Step-by-step explanation:

When 3-phenyl-2-butanol reacts with HCl it undergoes a substitution reaction to form 2-chloro-3-phenylbutane and water.

C₁₀H₁₄O + HCl ⇄ C₁₀H₁₃Cl + H₂O

The molar mass of 3-phenyl-2-butanol is 150.2 g/mol and the molar mass of 2-chloro-3-phenylbutane is 168.1 g/mol. The molar ratio is 1:1. Then, for 15.02 g of 3-phenyl-2-butanol, the theoretical yield is:

`15.02gC_(10)H_(14)O.(168.1gC_(10)H_(13)Cl)/(150.2gC_(10)H_(14)O) =16.81gC_(10)H_(13)Cl`