Answer: 0.1854
Explanation:
Given : Suppose that a particular candidate for public office is in fact favored by 48% of all registered voters in the district.
Let
be the sample proportion of voters in the district favored a particular candidate for public office .
A polling organization will take a random sample of n=500 voters .
Then, the probability that p will be greater than 0.5, causing the polling organization to incorrectly predict the result of the upcoming election :
![P(\hat{p}>0.5)=P(\frac{\hat{p}-p}{\sqrt{(p(1-p))/(n)}}>\frac{0.5-0.48}{\sqrt{(0.48(0.52))/(500)}})\\\\=P(z>0.8951)\ \ [\because\ z=(\frac{\hat{p}-p}{\sqrt{(p(1-p))/(n)}}]\\\\=1-P(z\leq0.8951)\ \ [\because\ P(Z>z)=1-P(Z\leq z)]\\\\ = 1-0.8146=0.1854](https://img.qammunity.org/2020/formulas/mathematics/high-school/yk6g7joj0eni8waw9ib6p4b4du32yvr5iu.png)
∴ Required probability = 0.1854