Question

Factors of 3x²±1÷3y² are

Answer 1

`(1)/(3) ,(1)/(y) , (1)/(y^(2) ) \textrm { and } (3x^(2) + 1)`

`(1)/(3) ,(1)/(y) , (1)/(y^(2) ), (√(3) x + 1) \textrm { and } (√(3) x - 1)`

Explanation:

We have to find the factors of the expression (3x² ± 1) ÷ 3y²

Now, (3x² ± 1) ÷ 3y² = (3x² + 1) ÷ 3y² and (3x² - 1) ÷ 3y²

Now, factors of (3x² + 1) ÷ 3y² are
`(1)/(3) ,(1)/(y) , (1)/(y^(2) ) \textrm { and } (3x^(2) + 1)`

Again the factors of (3x² - 1) ÷ 3y² are
`(1)/(3) ,(1)/(y) , (1)/(y^(2) ), (√(3) x + 1) \textrm { and } (√(3) x - 1)` (Answer)