Question

What are the solution(s) to the quadratic equation 50 – x2 = 0?

x= +2/5
O x = +673
x = 15/
no real solution

Answer 1

For this case we must solve the following quadratic equation:

`50-x ^ 2 = 0`

Subtracting 50 from both sides of the equation we have:

`-x ^ 2 = -50\\x ^ 2 = 50`

Applying square root to both sides of the equation we have:

`x = \pm \sqrt {50}\\x = \pm \sqrt {25 * 2}\\x = \pm \sqrt {5 ^ 2 * 2}\\x = \pm5 \sqrt {2}`

We have two real roots:

`x_ {1} = 5 \sqrt {2}\\x_ {2} = - 5 \sqrt {2}`

ANswer:

`x_ {1} = 5 \sqrt {2}\\x_ {2} = - 5 \sqrt {2}`