Question

A boy shoves his stuffed toy zebra down a frictionless chute, starting at a height of 1.75 m above the bottom of the chute and with an initial speed of 1.85 m/s. The toy animal emerges horizontally from the bottom of the chute and continues sliding along a horizontal surface with coefficient of kinetic friction 0.223. How far from the bottom of the chute does the toy zebra come to rest? Take g = 9.81 m/s2.__?___m

Answer 1

`d=8.63m`

Step-by-step explanation:

Given:

`h=1.75m`,
`v_i=1.85m/s`,
`u=0.223`

The work of friction is about the kinetic energy and also about the potential energy so:

`W_K=K_E+P_i`

`u*m*g*d=m*g*h+(1)/(2)*m*v^2`

Cancel the mass as a factor in each element

Solve to d'

`d=((v^2)/(2)+g*h )/(u*g)`

`d=((1.85^2)/(2)*9.8*1.75m)/(0.223*9.8)`

`d=8.63m`