Answer: a)
b)
c)
![(5)/(9)](https://img.qammunity.org/2020/formulas/chemistry/college/yeeu0k7by6gh63bu09bb12x2tnti3on4d8.png)
Explanation:
Since we have given that
There are green and yellow candies in each bag.
Bag A: Two thirds of the candies are yellow. What portion of the candies is green?
Part of yellow candies in bag A =
![(2)/(3)](https://img.qammunity.org/2020/formulas/mathematics/high-school/31tr2rxxvik3mwt65yx3r920qibzbnl6y1.png)
Part of green candies in bag A would be
![1-(2)/(3)\\\\=(3-2)/(3)\\\\=(1)/(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3wzpckdrnvki6z8yucxdiqaxqt13veu7pm.png)
Bag B: 29 % of the candies are yellow. What portion of the candies is green?
Percentage of candies are yellow = 29%
Portion of candies are green is given by
![1-(29)/(100)\\\\=1-0.29\\\\=0.71\\\\=(71)/(100)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2dwtv3of47daer9bsyy42n7y5xp57f94ia.png)
Bag C: 4 out of every 9 candies are yellow. What portion of the candies is green?
Portion of yellow candies =
![(4)/(9)](https://img.qammunity.org/2020/formulas/mathematics/high-school/46yotuwwa2zckk3ccpustduwvwhxw4w3ub.png)
Portion of green candies would be
![1-(4)/(9)\\\\=(9-4)/(9)\\\\=(5)/(9)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/wkynp95pmz7xa5wt27ti0u9xy5fzcbcjgi.png)
Hence, a)
b)
c)
![(5)/(9)](https://img.qammunity.org/2020/formulas/chemistry/college/yeeu0k7by6gh63bu09bb12x2tnti3on4d8.png)