Question

A projectile is launched from a point on level ground with initial speed 7.1 miles/hour and initial angle of 6 degrees above the horizontal. Air resistance may be ignored and normal earth gravity is present. Calculate the final value of the horizontal component of velocity in m/s just prior to the projectile striking the ground. [Note: Don't forget to convert units as needed.] g

Answer 1

Final value of horizontal component velocity will be -3.11 m/sec

Step-by-step explanation:

We have given initial velocity of the projectile u = 7.1 miles/hour

We know that 1 miles = 1609 m

Angle of projection
`\Theta =6^(\circ)`

And 1 hour = 3600 sec

So
`7.1miles/hour=(7* 1609m)/(3600sec)=3.128m/sec`

Now initial value of horizontal component
`u_(xi)=ucos\Theta =3.128cos6=3.11m/sec`

Now final value of horizontal component
`u_(xf)==-u_(xi)=-3.11m/sec`