Question

What is the height of a flag pole that casts a shadow of 100 feet when the angle of elevation of the sun is 62º? (to the nearest tenth) A) 44.2 feet B) 46.9 feet C) 156.4 feet D) 188.1 feet

Answer 1

Answer: D) 188.1 feet

Explanation:

Opposite side = X

adjacent side = 100feet

θ = 62°

Using the tangent formular

tanθ =opposite/adjacent

tan62° = x/100

Cross multiply

x= 100tan62°

x = 100 × 1.880726

x= 188.0726

x= 188.1 feet to the nearest tenth

Answer 2

Option D

188.1 ft

Explanation:

`Tan \theta=\frac {object}{shadow}`

Therefore,
`object=Tan\theta *` shadow

Substituting
`\theta` for
`62^(\circ)` and shadow for 100 ft

`Object=Tan 62^(\circ) * 100=188.0726465`

`Object \approx 188.1`