Answer:
3) 333.75 Grams
Step-by-step explanation:
2Al + 6HCl --- 2AlCl3 + 3H2
Work out and label what we know and workout Ar and Mr
Al = 67.15grams AlCl3
Al = Ar=27 Mr = 133.5
Mass/Mr == Moles
Al = 2.5 Moles AlCl3 = 333.75
Moles * Mr = Mass
2.5 * 133.5 = 333.75 Grams
4) Apply the same concept (numbers in front of elements are ratios, in this case 12 and 8) (when working out MR/AR ignore numbers in front)
1) Workout Mr/Ar (The relative atomic masses added up)
2) Do 36.72/(Mr of O2) = Your Moles
3) Do workout what the moles would be in the ratio 12:8 (Times/divide moles to find out the correct moles for 12:8
4) Times the new moles by the Mr of SO3
5) = Answer