Question

Can someone help me this is over due. Thank you to whoever can help.​

Answer 1

`▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪`

Let's solve ~

● Volume of cylinder :

`{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: \overbrace{  \underbrace{\underline{ \boxed{ \sf \pi {r}^(2) h\: }}}}`

Now, let's plug in the given values :

• Radius (r) = 10/2 = 5 cm

• Height (h) = 9 cm

Here we go !

`{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:\pi * (5) {}^(2) *9`

`{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:\pi * 25{}^{} *9`

`{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:225\pi`