Answer:
water: 80 gallons
premium antifreeze : 80 gallon s
Explanation:
Final solution is 160 gallon of 40% antifreeze
volume of pure antifreeze = 40% of 160 gallon =0.4*160= 64 gallons
Let say we mix x gallons water and y gallons premium antifreeze
amount of pure antifreeze = 80% of y
80*y/100 = 64
y = 80 gallons
x+y = 160 gallon s
x = 160-80=80 gallons
Therefore, you require
water: 80 gallons
premium antifreeze : 80 gallon s