Question

A flagpole consists of a flexible, 7.107.10 m tall fiberglass pole planted in concrete. The bottom end of the flagpole is fixed in position, but the top end of the flagpole is free to move. What is the lowest frequency standing wave that can be formed on the flagpole if the wave propagation speed in the fiberglass is 27302730 m/s?

Answer 1

To develop this problem we require the concepts related to Frequency and their respective way of calculating it.

The formula to calculate the frequency is given by

`f=(V)/(\lambda)`

Where,

`\lambda = wavelength`

`V= velocity`

For fundamental mode, wavelength is equal to 4 time the length.

Then,

`\lambda = 4L = 4*7.10m=28.4m`

Replacing in the first equation,

`f=(2730)/(28.4)\\`

`f= 96.12Hz`

Therefore the frequency is 96.12Hz