Question

How many oz. Of mixed nuts that contain 60% peanuts must Eugene add to 8 oz. Of mixed nuts that contain 30% peanuts to make a mixture with 48% peanuts?

Answer 1

12 oz

Explanation:

Let x represent the number of ounces of 60% mix Eugene must add. He wants the total mix to be 48% peanuts, so ...

0.30·8 + 0.60·x = 0.48·(8 +x)

2.4 + 0.60x = 3.84 + 0.48x . . . . . eliminate parentheses

0.12x + 2.4 = 3.84 . . . . . . . . . . . . . subtract 0.48x

0.12x = 1.44 . . . . . . . . . . . . . . . . . . . subtract 2.4

x = 1.44/0.12 = 12 . . . . . . . . . . . . . . .divide by 0.12

Eugene must add 12 oz of 60% peanuts to his mix.