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The graph of a line passes through the points (0, -2) and (6, 0). What is the equation of the line? CLEAR CHECK y = -2x + 6 y = 13x – 6 y = 3x – 2 y = 13x – 2

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For this case we have that by definition, the equation of a line in the slope-intersection form is given by:

Where:

m: Is the slope

b: Is the cut-off point with the y axis

According to the data of the statement we have two points through which the line passes:


(x_ {1}, y_ {1}): (0, -2)\\(x_ {2}, y_ {2}): (6,0)

We found the slope:


m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {0 - (- 2)} {6-0} = \frac {0 + 2} {6} = \frac {2} {6} = \frac {1} {3}

Thus, the equation is of the form:


y = \frac {1} {3} x + b

We substitute one of the points and find "b":


-2 = \frac {1} {3} (0) + b\\-2 = b

Finally, the equation is:


y = \frac {1} {3}x -2

Answer:


y = \frac {1} {3}x -2

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