Question

Consider the reaction of zinc sulfide and oxygen:

2 ZnS (s) + 3 O2 (g) → 2 Zno (s) + 2 SO2 (g)
What is the maximum mass of zinc oxide that can be produced by the reaction of 46.32 g of zinc sulfide and 15.5172 g of oxygen?
Feel free to round the given mass values to 4 significant figures.
Your answer must include the units. The tolerance is NOT part of the answer.
Numeric Response​

Answer 1

Mass = 0.004 g

Step-by-step explanation:

Given data:

Mass of zinc sulfide = 46.32 g

Mass of oxygen = 15.5172 g

Mass of zinc oxide = ?

Solution:

Chemical equation:

2ZnS + 3O₂ → 2ZnO + 2SO₂

Number of moles of ZnS:

Number of moles = mass/ molar mass

Number of moles = 46.32 g/ 97.5 g/mol

Number of moles = 0.46 mol

Number of moles of Oxygen:

Number of moles = mass/ molar mass

Number of moles = 15.5172 g/ 32 g/mol

Number of moles = 0.48 mol

Now we will compare the moles of oxygen and zinc sulfide with zinc oxide.

ZnS : ZnO

2 : 2

0.46 : 0.46

O₂ : ZnO

3 : 2

0.48 : 2/3×0.48 =0.32 mol

The number of moles of zinc oxide produced by oxygen are less so it will limiting reactant.

Mass of zinc oxide:

Mass = number of moles / molar mass

Mass = 0.32 mol / 81.38 g/mol

Mass = 0.004 g