Question

The opening course of the Dog Olympics involves the dogs running over a parabolic

ramp. The quadratic equation, R(x) = -0.05x2 +0.8x, models the ramp, where x is

the horizontal distance, in feet, of the ramp, and R(x) represents the height of the

ramp, in feet


According to the model, what is the horizontal distance of the ramp? Enter your

answer in the box below

Feet

Answer 1

x=13 feet

Explanation:

A ramp is between 1.96 and 1.80 feet, we will take 1.96

`If R(x) =-0.05x+0.8x` and R(x)=1.96 feet: we apply quadratic formula;
`\frac{-b+-\sqrt{b^(2) -4ac} }{2a}`, where a=-0.05, b=0.8 and c=-1.96, so

`\frac{-0.8+-\sqrt{0.8^(2)-4*(-0.05)*(-1.96) } }{2*(-0.05)},` solving
`x_(1)=13 ; x_(2) = 3,02`; we take the highest value of x, x=13