Question

The pressure of a sample of argon gas was increased from 3.50 ATM to8.34 ATM at constant temperature if the final volume of the argon sample was 18.3 L what was the initial volume of the argon sample assume ideal behavior

Answer 1

43.61 L

Step-by-step explanation:

• According to Boyle's law, the volume of a fixed mass of a gas and the pressure are inversely proportional at a constant absolute temperature.
• Mathematically,
  `P\alpha(1)/(V)`

`P=(k)/(V)`

• At varying volume and pressure

k = P1V1 = P2V2

In this case we are given;

Initial pressure, P1 = 3.50 atm

Final pressure, P2 = 8.34 atm

Final volume, V2 = 18.3 L

We are required to calculate the initial volume, V1,

Rearranging the formula;

`V1=(P2V2)/(P1)`

Therefore;

`Initial volume=((8.34atm)(18.3L))/(3.50atm)`

`=43.606`

Initial volume = 43.61 L