Question

A 10-kilogram mass is suspended from the end of a beam that is 1.2 meters long. The beam is attached to a wall. Find the magnitude and direction (clockwise or counterclockwise) of the resulting torque at point B.

Answer 1

The magnitude of the resulting torque
`=118 N.m`

Step-by-step explanation:

The resulting torque = Force
`*` perpendicular distance.

So the force
`=mass* gravity =10* 9.8 =98\ N`

Perpendicular distance
`= 1.2\ m`

Torque =
`F * d = 98* 1.2 = 117 .6 N\ m \approx 118 N\ m`

The direction will be clockwise as the force acting is downward and will pull the rod in clockwise direction.

So the torque is
`118\ N\ m` in cw(clockwise) direction.