Question

Find the value of x and y

Answer 1

a) For
`x=7` units

`y=7\sqrt2` units

b) For
`y=7\sqrt 6` units

`x=7\sqrt 3` units

c) For
`x=\sqrt 3` units

`y=\sqrt6` units

d) For
`y=4` units

`x=(4\sqrt 2)/(2)` units

Explanation:

Given triangle is a special 45-45-90 triangle.

Using the property of this triangle, if length of each leg is
`x` units then

`Hypotenuse = x\sqrt2` units.

For the given table
`x` is length of each leg of the right triangle and
`y` represents the length of hypotenuse.

a) For
`x=7` units

`y=7\sqrt2` units

b) For
`y=7\sqrt 6` units

`x=(7\sqrt 6)/(\sqrt2)=\frac{7\sqrt {2}\sqrt3}{\sqrt2}=7\sqrt 3` units

c) For
`x=\sqrt 3` units

`y=\sqrt 3\sqrt2=\sqrt6` units

d) For
`y=4` units

`x=(4)/(\sqrt2)` units

On simplifying.

`x=(4* \sqrt 2)/(\sqrt2* \sqrt2)`

`x=(4\sqrt 2)/(2)` units