Question

Two students withheld their scores to determine the strength of the model. Using the actual line of best fit equation, predict their scores based on their hours worked. Actual line of best fit: y= 4.81x + 17.4 Hours (x) | Score (y) 15 | ? 9 | ?

Answer 1

When x = 15, y = 89.55

When x = 9, y = 60.69

Explanation:

We are given the following information n the question:

The actual line of best fit equation predict the scores based on the number of hours worked by the students.

Actual line of best fit:

`y= 4.81x + 17.4`

where x is the number of hours worked and y is the predicted variable that is the scores.

We have to determine the score of students when they worked for 15 hours.

Thus, x = 15

Putting value in the equation:

`y = 4.81x + 17.4\\y= 4.81(15) + 17.4 = 89.55`

Score = 89.55

We have to determine the score of students when they worked for 9 hours.

Thus, x = 9

Putting value in the equation:

`y = 4.81x + 17.4\\y= 4.81(9) + 17.4 = 60.69`

Score = 60.69

Answer 2

The value of y is 89.55 at x=15 and 60.69 at x=9.

Explanation:

The equation of best fit line is

`y=4.81x+17.4`

where, y is scores of two students after x working hours.

We need to find the score after 15 and 9 hours.

Substitute x=15 in the given equation.

`y=4.81(15)+17.4`

`y=89.55`

Substitute x=9 in the given equation.

`y=4.81(9)+17.4`

`y=60.69`

Therefore, the value of y is 89.55 at x=15 and 60.69 at x=9.