Answer:
B (0.312, 0.364)
Explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence interval
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of

For this problem, we have that:
1289 randomly selected American adults responded to this question. This means that
.
Of the respondents, 436 replied that America is doing about the right amount. This means that
.
Determine a 95% confidence interval for the proportion of all the registered voters who will vote for the Republican Party.
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 95% confidence interval is:
B (0.312, 0.364)