Question

Two resistors of resistances R1 and R2, with R2>R1, are connected to a voltage source with voltage V0. When the resistors are connected in series, the current is Is. When the resistors are connected in parallel, the current Ip from the source is equal to 10Is. Part A Let r be the ratio R1/R2. Find r. Round your answer to the nearest thousandth. View Available Hint(s) r=R1/R2r = R 1 / R 2 = nothing

Answer 1

r=0.127

Step-by-step explanation:

When connected in series

Current = I

When connected in parallel

Current = 10 I

We know that equivalent resistance

in parallel R= R₁R₂/(R₂+ R₁)

In series R = R₁+R₂

Given that voltage is constant (Vo)

We also know that relationship between voltage ,current and resistance

V = I R

Vo = I (R₁+R₂) ------------1

Vo = 10 I (R₁R₂/(R₂+ R₁)) -------2

From above equations

10 I (R₁R₂/(R₂+ R₁)) = I (R₁+R₂)

10 R₁R₂ = (R₁+R₂) (R₂+ R₁)

10 R₁R₂ = 2 R₁R₂ + R₁² + R₂²

8 R₁R₂ = R₁² + R₂²

Given that

r = R₁/R₂

Divides by R₂²

8R₁/R₂ = ( R₁/R₂)²+ 1

8 r = r ² + 1

r ² - 8 r+ 1 =0

r= 0.127 and r= 7.87

But given that R₂>R₁ It means that r<1 only.

So the answer is r=0.127