Answer:
A) JK and LM will be parallel to each other.
Explanation:
On reflection on
line the x co-ordinate changes with y co-ordinate and y co-ordinate changes with x co-ordinate
![(x,y)\rightarrow (y,x)](https://img.qammunity.org/2020/formulas/mathematics/college/e87q7z2o986hh49sjh5jmpmg28k9rcczgn.png)
Points on line EF
![(0,6) , (-5,-2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/wfsaow8bhmd4kh8j6fb2ukakud68pitkw5.png)
On reflection of this line on
the new points we get for line JK are
![(6,0),(-2,-5)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/5ahzxgxla437mj4u5xgngfrevef4uel6pv.png)
Points on line GH
![(-4,9),(-9,1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/civ6tep595zmf4lny96l2g6a2e7lybjrj8.png)
On reflection on y=x line the new points we get for line LM are
![(9,-4),(1,-9)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/nqhwkaammmk6gglwcfwvouz6mx7zkvkb1j.png)
Slope of line JK
![m=(y_2-y_1)/(x2-x1)\\m=((-5)-0)/((-2)-6) \\m=(-5)/(-8)=(5)/(8)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/lumverwm1pptgicoy15ipvqmb5epkw997o.png)
Slope of line LM
![m=(y_2-y_1)/(x2-x1)\\m=((-9)-(-4))/(1-9) \\m=(-9+4)/(-8)=(-5)/(-8)\\m=(5)/(8)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/t4q35j1g4n8tub3ubvoh1ocsc8awzokge9.png)
For two line to be parallel, their slopes will be same.
![m_(JK) =(5)/(8) , m_(LM)=(5)/(8)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ndizod1f5h3nk1agjczw38fu27g3gwqniy.png)
Since slopes of lines JK and LM are same therefore we can say that these are parallel to each other.