Answer: Choise A and Choise B.
Explanation:
Given the following expression:
![3x+3(x+y)](https://img.qammunity.org/2020/formulas/mathematics/high-school/jt733upku19683qp6nn079eu4v4msupunl.png)
You can simplify it in order to find equivalent expressions.
Appying the Distributive Property, you get:
![3x+(3)(x)+(y)(3)=3x+3x+3y](https://img.qammunity.org/2020/formulas/mathematics/high-school/i4cdfxpcjuj7io8yzp64emgikw72odk1d1.png)
So:
1. If you add the like terms, you get this equivalent expression:
![3x+3x+3y=6x+3y](https://img.qammunity.org/2020/formulas/mathematics/high-school/q05yd9nqxsiy6z3tm11dapqnns3e1dolom.png)
2. But if you factor out 3, you get the following equivalent expression:
![3x+3x+3y=3(x+x+y)](https://img.qammunity.org/2020/formulas/mathematics/high-school/z4blubjd4lucpp866gtlht7ipk4ksiq5u1.png)
Therefore, the expression shown in Choice A and Choise B are equivalents to the expression
![3x+3(x+y)](https://img.qammunity.org/2020/formulas/mathematics/high-school/jt733upku19683qp6nn079eu4v4msupunl.png)