Question

My teacher gives me a block of some unknown material. I weigh it and find out that it weighs 22.5g. I then heat it up using 2067J of energy and notice that it only changes by 25 degrees celsius. What is its specific heat?

Answer 1

The specific heat of unknown material : 3.675 J/g °C

Further explanation

Given

mass of block = 22.5 g

Q = heat = 2067 J

Δt=25 °C

Required

The specific heat

Solution

Heat can be formulated :

Q = m.c.Δt

Input the value :

2067 J = 22.5 g x c x 25 °C

c = 3.675 J/g °C