Answer:
{8 cm, 15 cm, 17 cm}
Explanation:
we know that
The length sides of a right triangle must satisfy the Pythagoras Theorem
so
![c^2=a^2+b^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/xsm8kchig3pfblxfo10xa15jy2ias2waqf.png)
where
c is the greater side (the hypotenuse)
a and b are the legs (perpendicular sides)
Verify each case
case 1) we have
{5 cm, 15 cm, 18 cm}
substitute in the formula
![18^2=5^2+15^2](https://img.qammunity.org/2020/formulas/mathematics/high-school/30bc48cl1f5843us2mjkdu7uqv76p2lvea.png)
----> is not true
therefore
Sean cannot make a right triangle with this set of lengths
case 2) we have
{6 cm, 12 cm, 16 cm}
substitute in the formula
![16^2=8^2+12^2](https://img.qammunity.org/2020/formulas/mathematics/high-school/5nmw9pegh1exrxp4153irui3uidnogbp47.png)
----> is not true
therefore
Sean cannot make a right triangle with this set of lengths
case 3) we have
{5 cm, 13 cm, 15 cm}
substitute in the formula
![15^2=5^2+13^2](https://img.qammunity.org/2020/formulas/mathematics/high-school/j9jdw9pxyxqudhm14yn3zra1u1wunsar4s.png)
----> is not true
therefore
Sean cannot make a right triangle with this set of lengths
case 4) we have
{8 cm, 15 cm, 17 cm}
substitute in the formula
![17^2=8^2+15^2](https://img.qammunity.org/2020/formulas/mathematics/high-school/5oksmmk7fnkwdevk8bz16g5kp2x5758pte.png)
----> is true
therefore
Sean can make a right triangle with this set of lengths