Question

Ishani and John now try a problem involving a charging capacitor. An uncharged capacitor with C = 6.81 μF and a resistor with R = 5.8 105 Ω are connected in series to a 12.0 V battery. The switch is closed at time t = 0, allowing the capacitor to charge. Find the maximum charge on the capacitor and the maximum current through the resistor.

Answer 1

`Q=81.72*10^(-6)C`

`I=2.1*10^(-5)A`

Step-by-step explanation:

The maximum charge on the capacitor will be, at the end of the process, given by the formula (and for our values):

`Q=CV=(6.81*10^(-6)F)(12V)=81.72*10^(-6)C`

The maximum current on the resistor will be, at the beginning of the process, given by the formula (and for our values):

`I=(V)/(R)=(12V)/(5.8*10^(5)\Omega)=2.1*10^(-5)A`