Answer:
a) The carbon-carbon bonds rapidly alternate between single and double bonds.
Step-by-step explanation:
In benzene we have that the molecule is planar with an sp² hybridization that allow for three π bonds and the carbons atoms are also bonded together via sigma a sp² hibridization as well as one hydrogen atom. The alternation of or conjugation of the π bond allow the delocalization of these electron along the whole ring.
Therefore, a) is false the carbon-carbon bonds rapidly alternate between single and double bond. The electrons in the π bonds are completely delocalized through the six atoms in the ring.
b) is true since we have a sp² hybridization.
c) and d) are true for the reasons given previously.