Question

How many kilograms of solvent would contain 0.43 mol of CaO in a 2.5 molality solution

Answer 1

0.172 Kg

Step-by-step explanation:

Given data:

Kg of solvent = ?

Moles of solute = 0.43 mol

Molality = 2.5 m

Solution:

Formula:

m = moles / Kg of solvent

by putting values,

2.5 m = 0.43 mol / kg of solvent

Kg of solvent = 0.43 mol / 2.5 m

Kg of solvent = 0.172 Kg

Answer 2

0.024 kg CaO

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Chemistry

Aqueous Solutions

• Molarity = moles of solute / liters of solution

Atomic Structure

• Reading a Periodic Tables
• Using Dimensional Analysis

Step-by-step explanation:

Step 1: Define

0.41 mol CaO

2.5 M Solution

Step 2: Identify Conversions

1000 g = 1 kg

Molar Mass of Ca - 40.08 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of CaO - 40.08 + 16.00 = 56.08 g/mol

Step 3: Convert

1. Set up:
   `\displaystyle 0.43 \ mol \ CaO((56.08 \ g \ Cao)/(1 \ mol \ CaO))((1 \ kg \ CaO)/(1000 \ g \ CaO))`
2. Multiply:
   `\displaystyle 0.024114 \ kg \ CaO`

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs as our lowest.

0.024114 kg CaO ≈ 0.024 kg CaO