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√(x)*e^(x)
differentiate

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\text{Since (uv)'=u'v+v'u,}\\</p><p>(d(√(x)\cdot e^x))/(dx)=(d√(x))/(dx)e^x+ (d e^x)/(dx) √(x)\\</p><p>=(1)/(2√(x)) e^x + e^x √(x)

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