Question

Question 9 and 10 in picture, help please

Answer 1

9. 36.87°, 53.13°, 90°

10. 22.62°, 67.38°, 90°

Explanation:

9. From the diagram given with the question.

`\tan KLJ =(4y)/(3y) =(4)/(3)`

⇒ ∠ KLJ =
`\tan^(-1) ((4)/(3) )= 53.13` Degree.

Similarly,
`\tan KJL =(3y)/(4y) =(3)/(4)`

⇒ ∠ KJL =
`\tan^(-1) ((3)/(4) )= 36.87` Degree.

Therefore, the angles of the Δ KJL will be 36.87°, 53.13°, and 90°. (Answer)

10. From the diagram given with the question.

Similarly,
`\tan SQR =(5)/(12)`

⇒ ∠ SQR =
`\tan^(-1) ((5)/(12) )= 22.62` Degree.

Similarly,
`\tan QSR =(12)/(5)`

⇒ ∠ QSR =
`\tan^(-1) ((12)/(5) )= 67.38` Degree.

Therefore, the angles of the Δ SRQ will be 22.62°, 67.38°, and 90°. (Answer)