Question

A "swing" ride at a carnival consists of chairs that are swung in a circle by 11.0 m cables attached to a vertical rotating pole, as the drawing shows. Suppose the total mass of a chair and its occupant is 283 kg.

(a) Determine the tension in the cable attached to the chair.
(b) Find the speed of the chair.

Answer 1

a. tension of the cable attached to chair = 2.77kN

b. speed of the chair = 10.38m/s

Step-by-step explanation:

A. tension of the cable is calculated by mass of the chair multiply by gravitational acceleration.

Tension(T) = m*g

where, m= 283kg

length of cable = 11m

and g=9.8m/s2

tension = mg = 283*9.8

=2773.4 N = 2.77kN

b. speed of the chair =
`\sqrt{(tension)/(mass/length)}`

`\sqrt{(2773.4)/(283/11)}` = 10.38m/s