Question

300 people live in Burns, Oregon. As of Jan 1, 2013, 16 of them had diabetes. During 2013, 4 new cases were diagnosed. a) Calculate the prevalence (expressed as a percent) on Jan 1, 2013. b) Calculate the incidence during 2013 (express "per 1000"--dont' forget to include the time period). Partial credit will be given, so please show your work (and both answers) in the text box below.

Answer 1

a).- Prevalence=5.33%

b).-Incidence during 2013=14 people

Explanation:

Definition

Prevalence is the proportion of a population that has a specific characteristic in a given period.

For a representative sample, prevalence is the number of people in the sample with the characteristic of interest, divided by the total number of people in the sample.

The prevalence (expressed as a percent) on Jan 1, 2013 was

`(x)/(y) prevalence=( Number of people in sample with characteristic)/(Total Number   of people in sample)`

In percent:

Prevalence=
`(16)/(300)` *100

Prevalence=5.33%

Incidence is a measure of the number of new cases of a characteristic that develops in a population in a specified period

the incidence during 2013 is

n=(300-16)=284 people on Jan 1, 2013

Incidendence during 2013=
`( new cases)/( people sample) = 4/284 *1000=14.08\\The answer is 14 people`

Answer=14 people

Answer 2

a. 5.33% ( period: from "history" to the end of day, Jan 1, 2013

b. 66.67 per 1000, period, analysis after the whole year.

Explanation:

Prevalence (point prevalence)

C= Number of current diagnosed cases as at Jan, 1 2013

T= Total population as at Jan, 1 2013...

Prevalence (point of prevalence ) is given by (C/T)*100

b. Incidence... Given by

Let N= new discovered cases after Jan 1 2013.

Incidence is given by

( C+N)/ T * 10^n... Where n degree of sampling

In this case, n= 3; 10^3= 1000...