Answer:
We fail to reject null hypothesis.
Explanation:
Consider the provided information.
The mean daily coffee consumption for U.S. residents as 1.65 cups. Assume that a sample of 38 people from a North Carolina city consumed a mean of 1.84 cups of coffee per day, with a standard deviation of 0.85 cups.
![H_0:\mu=1.65](https://img.qammunity.org/2020/formulas/mathematics/college/uumnu5f9cem6i09al4925n0o0xz4u58jyn.png)
![Ha0:\mu\\eq 1.65](https://img.qammunity.org/2020/formulas/mathematics/college/7zuaulkp78oo3cxrixsf2e3dfm440c81bg.png)
According to the formula:
![t=(\bar x-\mu)/((\sigma)/(√(n)))](https://img.qammunity.org/2020/formulas/mathematics/college/nxuvze4la6r2kay4h79490q1za3eb9vt1g.png)
Substitute n=38, x = 1.84, μ = 1.65 and σ = 0.85 in above formula.
![t=(1.84-1.65)/((0.85)/(√(38)))](https://img.qammunity.org/2020/formulas/mathematics/college/7v2qy6ut6ko8mv8znncvefz6amcloip50z.png)
![t=1.38](https://img.qammunity.org/2020/formulas/mathematics/college/5fm1ey55t1eg7mlg1u6haci1sc6vsru8jm.png)
Now find degree of freedom (df)
df=n-1=37
α = 0.025
The appropriate t value with df =37 and α = 0.025 is 2.026
The t value which we calculated is less than 2.026, Hence, we fail to reject null hypothesis.