Question

Two long parallel wires carry currents of 1.77 A and 8.93 A . The magnitude of the force per unit length acting on each wire is 5.93×10−5 N/m . Find the separation distance of the wires expressed in millimeters.

Answer 1

533mm

Step-by-step explanation:

The concept that we need to apply here to find the radius is the Force in a Magnetic Field,

That is basically Force per unit length in terms of the current, which is given by,

`F= (\mu_0I_1I_2)/(2\pi R)`

Where,

`\mu_0` is the permeability constant

`I_i` is the current

R the radius

Re-arrange for Radius,

`R = (\mu_0 I_1I_2)/(2\pi R)`

Replacing our values

`R = (4\pi*10^(-7)(1.77)(8.93))/(5.93*10^(-5)2\pi)`

`R = 0.0533m`

Therefore the separation distance of the wires is 533mm