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What is the equation of a line that has a slope of -2/3 and a x-intercept of -3?

1 Answer

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For this case we have that, by definition, the equation of a line in the slope-intersection form is given by:


y = mx + b

Where:

m: It's the slope

b: It is the cutting point with the y axis

We have, according to the statement data that:


m = - \frac {2} {3}

So, the equation is of the form:


y = - \frac {2} {3} x + b

We also have that the line intersects the "x" axis at -3, that is, the line passes through the point
(x, y): (- 3,0)

We substitute to find "b":


0 = -\frac {2} {3} (- 3) + b\\0 = -2 + b\\b = 2

Finally, the equation is of the form:


y = - \frac {2} {3} x + 2

Answer:


y = - \frac {2} {3} x + 2

User Gwally
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