Answer:
(a)
J
b)
J
Step-by-step explanation:
(a)
= mass of the pumpkin = 3.2 kg
= height to which pumpkin is lifted = 1.2 m
= Work done in lifting the pumpkin
Work done in lifting the pumpkin is given as
![W_(g) = mgh](https://img.qammunity.org/2020/formulas/physics/high-school/ynegxfejg8u0kdk8ght6l9azb088gy7ivv.png)
![W_(g) = (3.2) (9.8) (1.2)](https://img.qammunity.org/2020/formulas/physics/high-school/svt241ky9inkhtujnqgxxavq53234gpz5c.png)
J
(b)
= Force applied on the pumpkin in vertical direction
= displacement in horizontal direction = 50 m
= Angle between applied force and displacement = 90
Work done in carrying the pumpkin is given as
![W_(p)= F d Cos\theta](https://img.qammunity.org/2020/formulas/physics/high-school/mqpzbdgzt2gds4hi3mqq03oq1ait07pwut.png)
![W_(p)= F d Cos90](https://img.qammunity.org/2020/formulas/physics/high-school/6phw8l4487r0nltuywvt05112y6tjyfgp4.png)
![W_(p)= F d (0)](https://img.qammunity.org/2020/formulas/physics/high-school/w8vkmivetxlgfx2pk79kjc2cbp9kmjlrr8.png)
J