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The quotient of the square of a number minus the cubed root of another number and the sum of those two numbers is nine. how can this relationship best be stated algebraically

1 Answer

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Answer:


\frac{x^(2) -\sqrt[3]{y}}{x+y}=9

Explanation:

we know that

The quotient means, divide the numerator by the denominator

In this problem

1) The numerator is "the square of a number minus the cubed root of another number"

Let

x ----> a number

y ----> another number

The algebraic expression of the numerator of the quotient is


x^(2) -\sqrt[3]{y}

2) The denominator is "the sum of those two numbers"

so

The algebraic expression of the denominator of the quotient is


x+y

3) The quotient of the square of a number minus the cubed root of another number and the sum of those two numbers is nine

Equate the quotient to the number 9

so

we have


\frac{x^(2) -\sqrt[3]{y}}{x+y}=9

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