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Which of the following equations defines a line that is parallel to the line y=-4/3x-4 and passes through the point (3,-1)

Which of the following equations defines a line that is parallel to the line y=-4/3x-example-1
User Pellegrino
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2 Answers

2 votes

Answer:

d

Explanation:

given that your slop is -4/3, plug the (x,y) point in to the equation of y = -4x/3 +b

-1 = -4 + b , b = 3

y = -4x/3 + 3

User Riva
by
8.0k points
3 votes

Answer:

D.

Explanation:

The given line is


y=-(4)/(3)x-4

Now, if the new line is parallel to the given one, that means it must have the same slope.


m=-(4)/(3)

We also know that the new line passes through point (3,-1).

Then, we use the point-slope formula to find the equation of the new line:


y-y_(1) =m(x-x_(1) )\\y-(-1)=-(4)/(3)(x-3)\\ y=-(4)/(3)x+4-1\\ y=-(4)/(3)x+3

Therefore, the line that passes through (3,-1) and it's parallel to the given line is:
y=-(4)/(3)x+3.

The image attached show these parallel lines.

Which of the following equations defines a line that is parallel to the line y=-4/3x-example-1
User Snoofkin
by
8.3k points

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