Question

Use the following balanced equation to answer the question below: 2C₇H₁₄+21O₂→14CO₂+ 14H₂O

If 8 moles of C₇H₁₄ are added to 43 moles of O₂, how many grams of water are made?

Answer 1

The answer to your question is: 516 g of water

Step-by-step explanation:

2 C₇H₁₄ + 21 O₂ → 14 CO₂ + 14 H₂O

8 moles 43 moles

Process

1.- Find the limiting reactant

Ratio theoretical O₂ / C₇H₁₄ = 21 / 2 = 10.5

Ratio experimental O₂ / C₇H₁₄ = 43 / 8 = 5.3

As the ratio diminishes the limiting reactant is O₂.

2.- Calculate the moles of water

21 moles of O₂ ------------- 14 moles of water

43 moles of O₂ ------------ x

x = (43 x 14) / 21

x = 28.67 moles of water

3.- Calculate the grams of water

Molecular mass of water= 18g

18 g ------------------------ 1 mol of water

x ------------------------ 28.67 moles of water

x = (28.67 x 18) / 1

x = 516 g of water