Question

A 1.40-kg ball tied to a string fixed to the ceiling is pulled to one side by a force F→ . where L = 1.40 kg. What is the tension in the string just before the ball is released and allowed to swing back and forth?

Answer 1

T=13.72N

Step-by-step explanation:

The tension before the ball is released have no angle is in rest at the same axis of the weight so:

∑F=0

Using Newton law in this case the ball is tied so tension before become to swing is

∑F=FN-T=0

`T=F_(N)`

`T=m*g`

`T=1.40Kg*9.8(m)/(s^2)`

`T=13.72N`