Answer:
3= 8.28 M
Step-by-step explanation:
Given data:
Mass of sucrose = 211.4 g
Density of solution = 1.34 g/mL
Molar mass of sucrose = 342 g/mol
Molarity = ?
Solution:
First of all we will calculate the moles of solute.
Number of moles of sucrose = mass/molar mass
Number of moles of sucrose = 211.4 g / 342 g/mol
Number of moles of sucrose = 0.62 mol
Volume:
Volume = mass/ desity
Volume = 100 g/ 1.34 g/mL
Volume = 74.63 mL
Volume = 0.075 L
Molarity:
Molarity = moles of solute / volume in litter
Molarity = 0.62 mol / 0.075 L
Molarity = 8.27 M