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Let f be the function defined by the f(x) = ln(-e^x + 2x)^k for some positive constant k. If f'(0) = 5, what is the value of k? A. 25 B. ln5 C. 5 D. -5 Show all work

Let f be the function defined by the f(x) = ln(-e^x + 2x)^k for some positive constant k. If f'(0) = 5, what is the value of k? A. 25 B. ln5 C. 5 D. -5 Show all work
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Let f be the function defined by the f(x) = ln(-e^x + 2x)^k for some positive constant k. If f'(0) = 5, what is the value of k?

A. 25
B. ln5
C. 5
D. -5

Show all work

User Dtheodor
by
8.0k points

1 Answer

3 votes

Answer:

k=(-5)

Solution in the picture above

Let f be the function defined by the f(x) = ln(-e^x + 2x)^k for some positive constant-example-1
User Lunster
by
7.5k points
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