Answer:
a) Slope of line 1 = (2/3)
b) Slope of line 2 = (-3/2)
c) Two lines are perpendicular.
Explanation:
Here, let the points of line 1 are A(1,0) and B(7,4)
Let the points of line 2 are A(7,0) and B(3,6)
Now for any two points, the slope m of the line is given as :
![m = (y_2 - y_1)/(x_2-x_1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/wluxmcrhp4qz1otntsnimbjrntkx295xx2.png)
⇒Slope of the line AB =
![m1 =( (4-0)/(7-1)) = (4)/(6) = (2)/(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/z8b82vomk47qkayauzmc0e2m4w7zl10x7v.png)
or, m1 = 2/3
and Slope of the line PQ =
![m2 =( (6-0)/(3-7)) = -(6)/(4) = -(3)/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/t6krc2gnbtinbxun5aqz16vbyjfl52pmxw.png)
or, m2 = -3/2
Now, TWO LINERS ARE SAID TO BE PERPENDICULAR if
m1 x m2 = -1 :with heir respective slope m1 and m2
Here,
![m1 * m2 = (2)/(3) * (-3)/(2) = -1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/mbspg51x5vqzd6gqgy3y5bbj4skm9g1fhr.png)
⇒ SLOPE OF AB x SLOPE OF PQ = -1
Hence, Line AB is perpendicular to the line PQ.