Question

What is the solution to this system of equations?

x = 12 − y
2x + 3y = 29

A.
x = 8, y = 4

B.
x = 6, y = 6

C.
x = 7, y = 5

D.
x = 9, y = 3

Answer 1

C

Explanation:

Given the 2 equations

x = 12 - y → (1)

2x + 3y = 29 → (2)

Substitute x = 12 - y into (2)

2(12 - y) + 3y = 29 ← distribute and simplify left side

24 - 2y + 3y = 29

24 + y = 29 ( subtract 24 from both sides )

y = 5

Substitute y = 5 into (1)

x = 12 - 5 = 7

Solution is x = 7, y = 5 → C