Final answer:
The statement A is false and the statement B is true. NaCl dissolves in water due to its large dipole moment and the strong dipole-dipole interactions between water molecules and the Na+ and Cl- ions. On the other hand, benzene does not dissolve NaCl because it has no dipole moment and lacks strong enough interactions with the ionic compound.
Step-by-step explanation:
The statement A is false and the statement B is true.
Statement A is false because the solubility of NaCl in water and benzene is not determined by the density of the solvents. It is determined by the intermolecular interactions between the solute (NaCl) and the solvent. NaCl dissolves in water because water is a polar solvent, and the strong dipole-dipole interactions between the water molecules and the Na+ and Cl- ions allow for the dissociation of NaCl. However, benzene is a nonpolar solvent, and it does not have strong enough interactions with NaCl to dissociate the ionic compound.
Statement B is true because NaCl dissolves in water due to its large dipole moment. Water has a positive end and a negative end, and these partial charges interact with the Na+ and Cl- ions, leading to the dissociation of NaCl. On the other hand, benzene has zero dipole moment because the molecule is symmetrical and its carbon-carbon bonds are nonpolar. Without a dipole moment, the interactions between NaCl and benzene are not strong enough to dissolve the ionic compound.
Therefore, statement A is false and statement B is true.