The width of the new card is 9 inches.
SOLUTION:
Given, we have to solve using equivalent ratios. Wayne has a recipe on a 3-inch-by-5-inch index card that he wants to enlarge to 15 inches long.
We have to find width of the enlargement
Now, dimensions of card is
![\bold{\frac{(3 \text { inch })}{(5 \text { inch })}}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2d1ax6oj1z8ihaet67d4h4uwhapvjzjfel.png)
Let the new width of card be n inches .
So, New dimensions of card is
![\bold{\frac{(n \text { inch })}{(15 \text { inch })}}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/jma4y5xzvx9w0df6fyokdsihm90scxabfq.png)
Then, equivalent ratio is
![\bold{(3)/(5)=(n)/(15)}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/f36w2wwqmsf91vnyfo6orc1qauy6ge42ci.png)
![\bold{(3)/(5)=(n)/(15) \rightarrow n=(3)/(5) * 15 \rightarrow n=3 * 3 \rightarrow n=9}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/bn1fnxt5l0wpqoe6udwq8a8fcpp7wsw10m.png)