Question

If you were to separate all of the electrons and protons in 1 g (0.001 kg) of matter, you’d have about 96,000 C of positive charge and the same amount of negative charge. If you placed these charges 4.5 m apart, how strong would the attractive force between them be?

Answer 1

`F = 4.096*10^18N`

Step-by-step explanation:

To solve this problem we need to apply the concept relate to Coulomb's law.

We know that the Force given by Coulomb is

`F = K (q_1q_2)/(r^2)`

Where ,

F= electrostatic force

q= electric charge

r= distance between charge centers

k= Coulomb constant =
`9.0*10^9 Nm^2/c^2`

We have the values only to replace in the equation, then we have,

`F = (9.0*10^9)(96000*96000)/(4.5^2)`

`F = 4.096*10^18N`