Question

PLS HELP
graph
y=−x+6
8x−4y=−16

Answer 1

The graph is shown below.

Explanation:

Given:

`y=-x+6\\8x-4y=-16`

In order to graph these two lines, we find their x and y intercepts.

The x intercept of
`y=-x+6` is at
`y=0`. So,

`0=-x+6\\x=6`

Therefore, x intercept is at
`(6,0)`

The y intercept of
`y=-x+6` is at
`x=0`. So,

`y=0+6\\y=6`

Therefore, y intercept is at
`(0,6)`

Now, similarly, we find the x and y intercepts of the other line.

The x intercept of
`8x-4y=-16` is at
`y=0`. So,

`8x-4(0)=-16\\8x=-16\\x=(-16)/(8)=x=-2`

Therefore, x intercept is at
`(-2,0)`

The y intercept of
`8x-4y=-16` is at
`x=0`. So,

`8(0)-4y=-16\\-4y=-16\\y=frac{-16}{-4}=y=4`

Therefore, y intercept is at
`(0,4)`

Now, we plot these pair of points on a graph and then join the pairs of lines.

The graph is shown below.